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Can I get some more physics help?
At what rate must a cylindrical spaceship rotate if occupants are to experience simulated gravity of 0.64 g? Assume the spaceship's diameter is 40 m , and give your answer as the time needed for one revolution
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- ?Lv 72 years agoFavorite Answer
It is simple. Centrifugal force should be equal to .64 g. rw^2 = 0.64 g
w = sqrt(0.64 g/r)=0.56
time needed for one revolution = 2 pi /w
=11.2 seconds
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