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eblox
eblox asked in Science & MathematicsChemistry · 2 years ago

How many moles of a gas sample are in a 10.0 L container at 373 K and 203 kPa?

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  • Roger the Mole
    Lv 7
    2 years ago
    Favorite Answer

    n = PV / RT = (203 kPa) x (10.0 L) / ((8.3144621 L kPa/K mol) x (373 K)) = 0.655 mol

  • Anonymous
    2 years ago

    Ideal gas equation

    PV=nRT. Substitute and solve for n. About 1 mole looking at the numbers.

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