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A saturated calcium hydroxide solution is prepared. 25mL of this solution is titrated with 0.05mol/L hydrochloric acid and 23.75mL are required for completed neutralization. Calculate the solubility product of calcium hydroxide.
1 Answer
- BobbyLv 72 years agoFavorite Answer
OH-_H+ = H2O
moles of HCl (H+) at the equivalence point = 0.05 mol / L* 0.025L = 0.00125 moles
moles of OH - at the equivalence point = 0.00125 moles because of the above equation
Mg(OH)2 = Mg2+ +2OH-
in the saturated solution we have 0.00125 moles of OH-
so we will have 0.000625 moles of Mg2+ ( in the solubility equation Mg2+ : OH- = 1:2)
Ksp = [Mg2+] * [OH-]^2
= 0.000625 * (0.00125)^2 = 9.76 *10^-10 .... there is your answer
