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In a titration, 16.84 mL of 0.00157 M Ba(OH)2 neutralized 17.2 mL of HCl solution. What is the molarity of the HCl? Answer in molarity?
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- Roger the MoleLv 72 years ago
Ba(OH)2 + 2 HCl → BaCl2 + 2 H2O
(16.84 mL) x (0.00157 M Ba(OH)2) x (2 mol HCl / 1 mol Ba(OH)2) / (17.2 mL HCl) = 0.00307 M HCl
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