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Chemistry acid-base question?
For a 0.1mol/L of monoprotic weak acid (HA) at a certain temperature, the ratio between the unionized and ionized molecules is 50:2, find the value of ionization constant (Ka) for the acid, HA.
1 Answer
- Trevor HLv 72 years agoFavorite Answer
Use the Ka equation:
Take the acid as HA
This will dissociate :
HA ↔ H+ + A-
Ka = [H+] [A-] /[HA]
Because dissociation is very small we can use 0.1M for [HA]
[H+] = 2/50*0.1 = 0.0004M
[A-] = 0.0004M
Ka 0.0004 * 0.0004 / 0.1
Ka = 1.6*10^-5 * 0.1
Ka = 1.6*10^-4