Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
3 Answers
- Dr WLv 72 years ago
how about we do this
.. PV = nRT
and we note that ALL 5 of those variables are + .. .there are no negative P, V, n, or T right?
*********
(i) if V and n are constant
. ..P = (nR/V) * T + 0.. .. . .P vs T plot is a line from the origin with a positive slope = (nR/V)
(ii) if T and P are constant
.. .V = (RT/P) * n + 0.. .. . V vs n is a line from the origin with a positive slope = (RT/P)
(iii) if T and n are constant
.. .P = (nRT) *(1/V) + 0.... . . P vs V is a curve with P = ∞ when V = 0... and P = 0 when V = ∞
.. . better yet
(iv).a plot of P vs 1/V = a straight line with slope = nRT and intercept = 0
see the generic plots that will work for your answer
- Anonymous2 years ago
Avogadro and Boyle were gay lovers.
- ?Lv 72 years ago
PV = nRT
P = pressure
V = volume in Liters
n = moles of gas, use Avagadro’s 6.022x10^23
R = ideal gas law constant
T = temperature in Kelvin (C + 273.15)
Temperature should be in absolute.
So R depends upon the units that you use. The most common used value for R, when dealing with gases, is 8.3144598 (kPa∙L)/(mol∙K), but you can use other values of R when you have different units:
Values of R and it’s units
8.3144598 __________ J⋅K−1⋅mol−1
8.3144598 ×10^3 ____ amu⋅m2⋅s−2⋅K−1
8.3144598 ×10^−2 ____ L⋅bar⋅K−1⋅mol−1
8.3144598 ___________ m3⋅Pa⋅K−1⋅mol−1
62.363577 ___________ L⋅Torr⋅K−1⋅mol−1
1.9872036 ×10^−3 ____ kcal⋅K−1⋅mol−1
8.2057338 ×10^−5 ____ m3⋅atm⋅K−1⋅mol−1
0.082057338 __________ L⋅atm⋅K−1⋅mol−1
Per Wiki: https://en.wikipedia.org/wiki/Gas_constant
I would solve for variable, like n first
n = PV/(RT)
then insert your given values