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Algebra Homework help!!!?
Rectangle A has a length 3 inches longer than its width. Rectangle B has a width 4 inches less than the width of A. B has a length twice the width of its own rectangle. Find the dimensions.
I tried setting it up 3+w=2w(l-4) but I’m not getting a correct answer.
2 Answers
- sepiaLv 78 months ago
Rectangle A has a length 3 inches longer than its width.
Rectangle B has a width 4 inches less than the width of A.
B has a length twice the width of its own rectangle.
Find the dimensions.
3 + w = w - 4
- ?Lv 72 years ago
There are only 3 equations with 4 unknowns
Rectangle A has a length 3 inches longer than its width.
L = W + 3
Rectangle B has a width 4 inches less than the width of A (Y = width of B)
Y = W - 3
B has a length twice the width of its own rectangle (X = length of B)
X = 2Y
In order to solve
there must be a 4th equation
Is there any other information?
