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I need some help with physics?
You are standing next to the edge of a canyon when you exert superhuman strength and throw a ball straight up at a velocity of 456 m/s. You see it hit the canyon floor 145.5m below. What is the TOTAL time the ball spends in the air?
2 Answers
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- Anonymous2 years agoFavorite Answer
y = y0 + v0 t - 1/2 g t^2
or
1/2 g t^2 - v0 t - (y0 - y) = 0
imposing y = 0 on get
4.9 t^2 - 456 t - 145.5 = 0
t = 46.69 s (neglecting the negative solution)
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