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Bob asked in Science & MathematicsPhysics · 2 years ago

Some more physics help?

At what velocity must you shoot out a pumpkin from a cannon that your friend standing on the edge of a 565m tall canyon can catch it at a velocity of 0 m/s?

3 Answers

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  • Anonymous
    2 years ago
    Favorite Answer

    must be

    1/2 m v^2 = m g h

    v = (2 g h)^1/2

    v = (2*9.8*565)^1/2 = 105.23 m/s = 378.84 km/h

  • 2 years ago

    2*9.8*565 = v^2 or v = 105.23 m/s

  • 2 years ago

    Thank you so much!

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