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3 Answers
- PopeLv 72 years agoFavorite Answer
Below is the sketch along with a few of the easier angles, which should require no explanation.
x + y = 120°
Applying the sine rule:
In ∆ADE, DE = AEsin(20°)/sin(40°)
In ∆ABE, EB = AEsin(20°)/sin(100°)
DE : EB = sin(100°) : sin(40°)
DE : EC = sin(100°) : sin(40°) ... (because of isosceles ∆ BCE)
In ∆CDE,
DE/sin(x) = EC/sin(y)
sin(x) : sin(y) = DE : EC
sin(x) : sin(y) = sin(100°) : sin(40°)
sin(x) : sin(y) = sin(80°) : sin(40°) ... (because sin(100°) = sin(80°))
So we have this:
sin(x) : sin(y) = sin(80°) : sin(40°) and x + y = 120°
x = 80°, y = 40°
The angle you required is x.
x = 80°
- billrussell42Lv 72 years ago
AEB = 180 –20–100 = 60º
DEC = AEB = 60º
AED = 180 – AEB = 120º = BEC
ADE = 180 – 20 – 120 = 40º
BCE = 180 – 30 – 120 = 30º
Triangle DCE
x + y + 60 = 180
x + y = 120