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Chemistry molar concentration question!?
Suppose you dissolve 1.00g of calcium chloride in 500.0mL of water. You then take 5.00mL of that solution and dilute it to 25.0mL. What is the molar concentration of the final solution?
2 Answers
- Roger the MoleLv 71 year ago
(1.00 g CaCl2) / (110.984 g CaCl2/mol) / (0.5000 L) x (5.00 mL / 25.0 mL) =
0.00360 mol/L
- hcbiochemLv 71 year ago
Molar mass of CaCl2 is 111.0 g/mol
1.00 g / 111.0 g/mol = 9.01X10^-3 mol
Original solution molarity = 9.01X10^-3 mol / 0.5000 L = 0.0180 mol/L
For the dilution:
M1V1 = M2V2
0.0180 mol/L (5.00 mL) = M2 (25.0 mL)
M2 = 3.60X10^-3 M CaCl2
