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What are the minimal air to gas mixtures for combustion for the hydrocarbons listed below? ?
At what ratios would methane, ethane, propane, butane, and pentane combust in normal air?
2 Answers
- ?Lv 71 year agoFavorite Answer
Your question seeks the LOWER FLAMMAABLE LIMIT for these gasses. (In Volume %)
CH4: 5%, ethane: 3%, propane: 2.1%, butane: 1.6, pentane: 1.5%
- davidLv 71 year ago
methane === CH4 + 2O2 ==> CO2 + 2H2O
1mole CH4 reacts with 2 moles O2 === since the air is only 20% O2 ... then it requires 5 times as much air ..
Air / methane = 10 / 1 <<< ans. for methane
Ethane ... 2C2H6 + 7O2 == > 4CO2 + 6H2O
Air / ethane = (7x5)/2 = 35/2 >>> ans. for ethane
do the others the same way .. start with a balanced eq.
Propane ... 25/1
Butane --- 65/2
Pentane --- 40/1
