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? asked in Science & MathematicsMathematics · 1 year ago

Geometry Angles Question?

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3 Answers

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  • Engr. Ronald
    Lv 7
    1 year ago

    solving for Angle B

    m∠B + m∠C= 90

    m∠B +  55 = 90

    m∠B  = 90 - 55

    m∠B = 35°

    since ∠B ≅  ∠ECD therefore  ∠ECD = 35°

    solving for ∠BCE

    m∠DCE +m∠BCE +  m∠ACB = 180°

     35 +  m∠BCE + 55 = 180

      m∠BCE + 90 = 180

      m∠BCE = 180 - 90

     m∠BCE = 90° answer//

  • Pramod Kumar
    Lv 7
    1 year ago

    ∠ABC (ie x )  = 180° - ( ∠A + 55° )  =  180° - ( 90° + 55° ) = 35°

    Hence ∠ DCE  =  x  =  35°

    Now ∠ DCE  + ∠ BCE + ∠ ACB  =  180°

    => 35° +  °BCE + 55°  =  180°

    => ∠ BCE  =  90°  .............. Answer

  • jacob s
    Lv 7
    1 year ago

    Angle B= 180-90-55=35

    Angle ECD=35

    Angle BCE=180-35-55=90

    Angle BCE=90 degrees

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