Help me solve please!?

Question

The half life of radium is 1690 years. If 50 grams are present now how much will be present in 970 years?

Round to nearest thousandth

? · Answer

r₀ is the starting amount
r(t) is the amount remaining after t years.

llaffer · Answer

I answered an almost identical question, from you, yesterday.  It's the same problem with slightly different numbers.

You can follow the same steps and do this one.

Learn from your questions.  We're not here to do your homework for you.

https://answers.yahoo.com/question/index?qid=20200413035643AAi25Fj

Wayne DeguMan · Answer

R(t) = 50 x (1/2)^(t/1690)

Hence, when t = 970 we have:

R(970) = 50 x (1/2)^(970/1690) => 33.6 grams

:)>

stanschim · Answer

A(t) = Ce^(-rt)

At t = 0 there are 50 grams, so C = 50.

A(t) = 50e^(-rt)

at t = 1690, there will be 1690/2 = 25 grams.

25 = 50e^(-1690r)

25/50 = e^(-1690r)

ln(25/50) / (-1690) = 0.000410146261 = r

A(t) = 50e^(-0.000410146261t)

A(970) = 33.5884 grams

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