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Tucker
Tucker asked in Science & MathematicsMathematics · 12 months ago

simplify: (cscθ secθ) / cotθ? I got cosθ^2 is this correct?

4 Answers

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  • Wayne DeguMan
    Lv 7
    12 months ago
    Favorite Answer

    cosecθ = 1/sinθ, secθ = 1/cosθ and cotθ = cosθ/sinθ

    so, (cosecθsecθ)/cotθ => [(1/sinθ)(1/cosθ)]/(cosθ/sinθ)

    i.e. (1/sinθcosθ)(sinθ/cosθ)

    Hence, 1/sin²θ => cosec²θ

    :)>

  • ?
    Lv 7
    12 months ago

    (csc(θ) sec(θ))/cot(θ)

    = sec^2(θ)

  • moe
    Lv 7
    12 months ago

    Yes you are right.

    (csc(theta)sec(theta) / cot(theta)

    Since. csc(thata) = 1/sin(theta)

               sec(theta) = 1/cos(theta) and 

               cot(theta) = cos(theta)/sin(theta)

    we get:

    (csc(theta)sec(theta)) / cot(theta)

    = (1/sin(theta) * 1/cos(theta))/ cost(theta)/sin(theta)

    = 1/sin(theta)* 1/cos(theta) / sin(theta)/cos(theta)

    = 1/[cos(theta) * cos(theta)] = 1/cos^2(theta) 0r 

    = sec^2(theta)

  • ted s
    Lv 7
    12 months ago

    NO ; try sec² Θ.....

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