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solve sec²θ - 2tanθ - 3 = 0. state the general solution to the nearest degree.?

show work please :)

2 Answers

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  • sepia
    Lv 7
    12 months ago

    sec²θ - 2tanθ - 3 = 0

    sec^2(θ) = 2 tan(θ) + 3

    Solutions:

    θ ≈ 2 (3.1416 n - 0.96084), n element Z

    θ ≈ 2 (3.1416 n + 0.60996), n element Z

    θ ≈ 2 (3.1416 n + 1.2548), n element Z

    θ ≈ 2 (3.1416 n - 0.31596), n element Z

  • Ash
    Lv 7
    12 months ago

    sec²θ - 2tanθ - 3 = 0

    (1 + tan²θ) - 2tanθ - 3 = 0

    tan²θ - 2tanθ - 2 = 0

    tanθ = [-(-2)±√((-2)²-4*1*(-2))]/2

    tanθ = (2±√12)/2

    tanθ = (2±2√3)/2

    tanθ = 1±√3

    θ = arctan (1±√3)

    θ = (180n - 36)° , (180n + 70)°  for n = -∞ to ∞

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