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solve sec²θ - 2tanθ - 3 = 0. state the general solution to the nearest degree.?
show work please :)
2 Answers
- sepiaLv 712 months ago
sec²θ - 2tanθ - 3 = 0
sec^2(θ) = 2 tan(θ) + 3
Solutions:
θ ≈ 2 (3.1416 n - 0.96084), n element Z
θ ≈ 2 (3.1416 n + 0.60996), n element Z
θ ≈ 2 (3.1416 n + 1.2548), n element Z
θ ≈ 2 (3.1416 n - 0.31596), n element Z
- AshLv 712 months ago
sec²θ - 2tanθ - 3 = 0
(1 + tan²θ) - 2tanθ - 3 = 0
tan²θ - 2tanθ - 2 = 0
tanθ = [-(-2)±√((-2)²-4*1*(-2))]/2
tanθ = (2±√12)/2
tanθ = (2±2√3)/2
tanθ = 1±√3
θ = arctan (1±√3)
θ = (180n - 36)° , (180n + 70)° for n = -∞ to ∞