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? asked in Science & MathematicsMathematics · 11 months ago

Evaluate the integral.?

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1 Answer

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  • Break it into 2 integrals:

    int(3 * dx , x = -4 , x = 0) + int((6 - x^2) * dx , x = 0 , x = 4)

    3x [-4 , 0] + (6x - (1/3) * x^3) [0 , 4]

    3 * (0 - (-4)) + 6 * (4 - 0) - (1/3) * (4^3 - 0^3) =>

    3 * 4 + 6 * 4 - (1/3) * 64 =>

    36 - 64/3 =>

    108/3 - 64/3 =>

    44/3

    Before we get too crazy though and say that 44/3 is the answer, we need to acknowledge that the function isn't continuous or differentiable when x = 0.  If you can plug in something that says that we can't integrate it, then you can try that first.

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