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A cart with mass 350 g moving on a frictionless linear air track at an initial speed of 1.2 m/s undergoes an elastic collision with an initi?
A cart with mass 350 g moving on a frictionless linear air track at an initial speed of 1.2 m/s undergoes an elastic collision with an initially stationary cart of unknown mass.
After the collision, the first cart reverses its original direction with final speed of 0.59 m/s.(a) Now what is the mass of the second cart?(b) Now what is the speed of the second cart after impact?
1 Answer
- Old Science GuyLv 711 months agoFavorite Answer
I'll use
M1V1+M2V2=M1V3+M2V4 conservation of momentum
and
1/2 M1V1^2 +1/2 M2V2^2 = 1/2 M1V3^2 + 1/2 M2V4^2
1/2 cancels
M1V1^2 + M2V2^2 = M1V3^2 + M2V4^2 energy conserved
because this is an elastic collision
350(1.2) + 0 = 350(-0.59) + M2V4
M2V4 = 626.5
and
350(1.2^2) + 0 = 350(-059^2) + M2V4^2
M2V4^2 = 382.165
M2V4 V4 = 382.165
V4 = 382.165 / M2V4 = 382.165 / 626.5 = 0.61 m/s
so
M2 = M2V4 / V4 = 626.5 / 0.61 = 1027 g
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