Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Trending News

Promoted
bill
Lv 5
bill asked in Science & MathematicsMathematics · 9 months ago

Algebra Question?

So it's been quite some time since I've used algebra. I started with y= (x+2)(x+1) and I need to express x in terms of y. So far I've done the following

Start

y=(x+2)(x+1)

y=x^2 + 2x + 3x +2

y=x^2 + 5x +2

y - 2=x^ + 5x

y - 2 -5x=x^2

I'm drawling a blank on how to remove the exponent to show the equation further broken down to only have x=  on one side. Is this accurate thus far and can you please provide the steps to break down further?

Thank you -

1 Answer

Relevance
  • micatkie
    Lv 7
    9 months ago

    y = (x + 2)(x + 1)

    y = x² + 3x + 2

    y = [x² + 3x + (3/2)²] + 2 - (3/2)²

    y = [x + (3/2)]² - (1/4)

    [x + (3/2)]² = y + (1/4)

    [x + (3/2)]² = (4y + 1)/4

    [x + (3/2)] = ±√(4y + 1)/2

    x = [-3 ± √(4y + 1)]/2

Still have questions? Get your answers by asking now.