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How do you describe the roots of the equation shown below? ?
64x^2 - 16x + 1 = 0
a) One real, double root
b) Two real, rational roots
c) There are two complex roots
d) There are two real, irrational roots
2 Answers
- ?Lv 76 months ago
The idea is to look at the discriminant b² - 4ac.
If its = 0, one (hence double) root.
If its > 0, two distinct real roots.
If its < 0, two distinct complex roots.
So, compute the discriminant. What do you get?
In what category does it fall?
Your final answer?
Done!
Hopefully no one will spoil you the answer thereby depriving you from your personal enhancement; that would be very inconsiderate of them.
- stanschimLv 76 months ago
a = 64
b = -16
c = 1
b^2 - 4ac = (-16)^2 - 4(64)(1) = 0
a) One real, double root. <==answer
