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homework help: How many grams of ammonium hydroxide are needed to completely neutralize 2.19 mols of hydrochloric acid?
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- Roger the MoleLv 74 months ago
NH4OH + HCl → NH4Cl + H2O [balanced as written]
(2.19 mol HCl) x (1 mol NH4OH / 1 mol HCl) x (35.0458 g NH4OH/mol) =
76.8 g NH4OH
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