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Charged particle in Circular path. . .?
A 1.31144 μC charged particle with a kinetic energy of 0.13621 J is placed in a uniform magnetic field of magnitude 0.107491 T.
If the particle moves in a circular path of radius 1.44042 m, find its mass.
1 Answer
- ?Lv 74 weeks agoFavorite Answer
equate the magnetic force to the centripetal force:
qvB = mv²/r → → v = qBr / m
plug into KE formula:
KE = ½mv² = ½m(qBr/m)² = (qBr)² / 2m, and so
m = (qBr)² / 2*KE
... = (1.31144E-6C * 0.107491T * 1.44042m)² / (2 * 0.13621 J)
... = 1.51E-13 kg
