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2. If the capacitor in Q 1 is charged to a potential difference of 12 V, then discharged through an 0.8 MΩ resistance as shown?
C= 5 uF, R=0.8M
1 Answer
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- billrussell42Lv 72 weeks ago
τ = RC = 5 µF x 0.8 MΩ = 4 sec
Q = CV = 5 µF x 12 v = 60 µC
v = v₀e^(–t/τ)
v = 12e^(–1) = 4.41 volts
zero
voltage on a cap, discharging
v = v₀e^(–t/τ)
v₀ is the initial voltage on the cap
v is the voltage after time t
R is resistance in ohms
C is capacitance in farads
t is time in seconds
RC = τ = time constant
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