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Richard
Richard asked in Science & MathematicsPhysics · 1 week ago

What is the voltage drop across the 3 Ohm resistor?

a. 3 V

b. 9 V

c. 1.5 V

d. 4.5 V

Attachment image

5 Answers

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  • Jim
    Lv 7
    1 week ago
    Favorite Answer

    Find the current, V=IR(total) so I = V/R(total)

    V/R(total) = 9/6 = 1.5 amp

    Find the Voltage drop, V = IR₃

    IR₃ = 1.5 × 3 = 4.5 v

  • Philomel
    Lv 7
    1 week ago

    V(3)= (9*3)/6=27/6=4.5v.

  • ?
    Lv 7
    1 week ago

    3 Ω is half of the resistance of the circuit, so the voltage drop is

    ½*9V = 4.5 V ◄ d

    total resistance R = 6 Ω

    so current I = V/R = 9V / 6Ω = 1.5 A

    and the drop across any resistor is I*R = 1.5A * R

    Attachment image
  • oubaas
    Lv 7
    1 week ago

    V(3) = V*3/(1+2+3) = 9*3/6 = 4.5 V 

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  • nyphdinmd
    Lv 7
    1 week ago

    Current I = 9V/(2+3+1) Ohms = 9/7 A

    V3 = I*3Ohms = 27/7 A = 3.86 A

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