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I solved this sum but I am not sure about the method. I needed some help solving this please? I found the sum from Walker and Resnick's book?
In an amusement park rocket ride, cars are suspended from 4.25-m cables attached to the rotating arms at a distance of 6.00 m from the axis of rotation. The cables swing out at an angle of 45.0° when the ride is operating. Consider the mass of a rocket car is 75 kg.
a) Find centripetal force on the rocket.
b) What is the angular speed of rotation of the rocket?
c) Find the radial and tangential acceleration of the rocket
1 Answer
- oubaasLv 74 weeks ago
L' = (6+4.25/√2) = 9.00 m
ω^2*L' = g
ω^2*9.00 = 9.806
ω^2 = 9.806/9 = 1.090
b) angular speed ω
ω = √1.090 = 1.044 rad/sec
a) centripetal force CF on the rocket
CF = m*ω^2*L' = 75*1.090*9 = 735 N
c) radial (ar) and tangential (at) acceleration of the rocket
ar = ω^2*L' = 1.090*9 = 9.806 m/sec^2 = g
at = 0 (constant ω)
