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If the concentration of product C at equilibrium was measured to be 0.456 what are the initial conditions?
1 Answer
- hcbiochemLv 71 day ago
The initial concentrations were given to you. You are asked to find the equilibrium concentrations of everything. You can do this by determining how much C was consumed and then using the stoichiometry of the balanced equation to calculate the other concentrations:
molarity of C consumed = 0.651 - 0.456 = 0.195 M
0.195 M C X (1 M D / 3 M C) = 0.065 M D consumed. So,
equilibrium [D] = 0.754 - 0.065 = 0.689
0.195 M C X (2 M A / 3 M C) = 0.130 M = [A]
0.195 M C X (1 M Y / 3 M C) = 0.065 M = [Y]
K = [C]^3 [D]/[A]^2[Y]
K = (0.456)^3 (0.689) / (0.130)^2 (0.065) = 59.5
