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If a gas changes from 21.09 L to 25.83 L with a constant external pressure of 1.38 atm, what is the work, w (in kJ)?
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- Roger the MoleLv 75 days ago
(21.09 L - 25.83 L) x (1.38 atm x (101.325 kPa / atm)) = -662.787 J = -0.663 kJ
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