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If 8.00 moles of NH₃ of and 10.00 moles of O₂ react in the following reaction, how many moles of which reactant will be left over?
If 8.00 moles of NH₃ of and 10.00 moles of O₂ react in the following reaction, how many moles of which reactant will be left over?
4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g)
1 Answer
- hcbiochemLv 75 days ago
Identify the limiting reactant:
8 mol NH3 X (5 mol O2 / 4 mol NH3) = 10 mol O2
The two reactants are combined in their stoichiometric ratio. Assuming that the reaction goes to completion, neither reactant will remain. Both reactants will be completely consumed.