Dean

Does anyone have the mass moment of inertia for a typical car wheel ?

(all of it, rim and tyre combined)

Thanks

A bowling ball enters the lane at 10 m/s with no rotation (sliding only) the sliding friction force is split evenly between adding rotation to the ball and decelerating the ball directly ( f / m ), find the time for the ball to reach synchronous speed.

m = ball mass = 10 kg

r = ball radius = 0.1 m

µ = friction co-efficient = 0.1

g = 10.0 m/s/s

A 20 kg block is at rest on a 30 degree incline, it is to be pushed to a rest point 12 metres up the incline.

The pushing force starts at an unspecified value and diminishes constantly to zero at the rest point.

Calculate the starting force and the maximum velocity of the block.

The friction co-efficient is 0.25

g = 9.8 m/s/s

How fast would a car go if you quadrupled its power ?

Ignore rolling resistance.

v = original velocity

V = new velocity

p = original power

P = new power

If an orca can travel at 30 mph under water, what power does this take ?

Assume its specific Cd is the same as a family car ie 0.45

A locomotive of mass 124,000 kg pulls a train of 30 carriages where at 8.0 m/s it is still accelerating at 0.1 (m/s)/s, what is the maximum incline angle the locomotive and train can manage at the same speed ?

g = 9.81 (m/s)/s

each carriage = 60,000 kg mass

The total rolling resistance force for the locomotive and carriages = 48,000 N

A cyclist can produce a maximum 200 Watts at the drive wheel.

The co-efficient of rolling resistance for the cycle and rider is 0.03

Total mass = 80 kg

local g = 9.81 m/s/s

When she is travelling along a level road into a headwind of 4 m/s her maximum speed is 4.71 m/s.

What is her top speed if she turns around and pedals in the opposite direction ?

recently i have been unable to post an answer on yahoo questions, any ideas ?

i dont have access to computer download, if i can do it as requested, please let me know how, and what leads to obtain.

A wheel rolls without slipping down an incline, calculate the final velocity.

I = mass moment of inertia = 3.5 kg-m²

u = initial velocity = 5 m/s

s = distance rolled = 25 meters

m = mass = 25 kg

r = rolling radius = 0.4 meters

A = incline angle = 12.5°

g = local gravity rate = 9.81 (m/s)/s

k = rolling resistance co-efficient = 0.03

The drag co-efficient (Cd) = 0.20

The rolling resistance co-efficient (k) = 0.03

g = 9.81 (m/s)/s

m = mass including rider = 300 kg

The air drag force = Cd * v²

The rolling resistance force = m * g * k

Top speed please in mph (± 1 mph is fine)

In linear motion, the work done (J) is given by :

force applied (N) * distance travelled (m)

Is the rotary equivalent :

Torque (N-m) * radians turned through

?

Thanks in advance

dean

Ive saved an equation on a word document as a building block, and would like to re insert at a new location for editing.

Help appreciated.

for a week or so i havnt been able to submit any answers an yahoo, any ideas ?

The submit box doesnt appear.

are at a distance of 10 metres when released from rest, what are the individual velocities of each mass when the distance between has closed to 5 metres ?

m1 = 125 kg

m2 = 25 kg

Then at impact both have a velocity, how do you work out these two velocities ?

is it the earths centre, or the earth - moon barycentre ?