Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
LadyGelfling
Can a job force you to take breaks?
I live in a state that doesn't have any hard and fast rules regarding requirements for if breaks have to be given based on how many hours you work, but I have a different type of question.
I work at a place that puts a high regard on labor cost vs. revenue. If revenue at that moment is not high enough to cover current labor cost (per whatever calculation the company is using) they will force an employee to clock out and take a half-hour to hour break in order to bring the ratio back up. I have been asked to do this on days where I have been scheduled to work for only 4 hours (23 for the whole week).
Is this a legal practice? I have tried googling this question but all I can find is articles on not getting paid for lunch breaks. Any help is appreciated.
9 AnswersOther - Careers & Employment7 years agoConcavity Diagram Question?
I'm working on curve sketching and I've got pretty much everything down. I'm down to calculating concavity intervals and here's another one where I don't know how the book got its answer. I've already calculated f"(x), which is:
(-6(2x^3 - 45x^2 - 225) / (x^2+2x-15)^3
and my answer matches the book, but then it goes on to find an inflection point at 22.7 by doing the following:
2x^3 - 45x^2 - 225 = 0
x ≈ 22.7
with a note in red that says "found by calculator"
I already knew about the vertical asymptotes at -5 and 3, but where did 22.7 come in? How is that found by a calculator? What formula would you put in to find that? I am going to be taking a test soon on this chapter and would like to know the steps so that if I need to do this I will know how. Any help is greatly appreciated.
1 AnswerMathematics8 years agoQuotient Rule Question?
I'm working an example problem, so the answer is already there, but I'm not seeing how they got to where they did.
R(t) = (63t - t^2)/(t^2 + 63)
Using the quotient rule, the first step gives:
((t^2 = 63)(63 - 2t) - (63t - t^2)(2t))/(t^2 + 63)^2
which is the same thing I got
then they show that ultimately the answer is:
(-63(t - 7)(t + 9))/(t^2 + 63)^2
and this is where I'm lost. Can someone show me how the book reached this conclusion? I'd really appreciate it.
2 AnswersMathematics8 years agoMy cat ate some honey then started spazzing, is it because of the sugar?
I was having my morning bagel with cream cheese and honey and he was curious, so I put some honey on my finger and he tasted some, twice. Then he spazzed.
By spazzing, I mean he started running around and just acting like a nut, kind of like cats do sometimes late at night when they get that weird burst of energy out of nowhere. He was randomly batting at toys, running up at me and doing the puffy tail back arch thing then running off, jumping on his kitty tower then running down the hallway. He did it for about 5 minutes then was "normal" again.
I don't think honey is harmful, at least not in small doses, and this is the first time he's had it. My other cat tried to get some off of my plate and he got some on his nose and immediately pulled back and started shaking his head trying to get it off once it got stuck on there. Any ideas? Has anyone else seen this happen?
2 AnswersCats8 years agoCommercial Paper Homework Question (Accounting)?
I'm in the middle of doing a homework problem and I'm dealing with an "it's so easy it's complicated" scenario right now.
Here's the necessary info to solve the problem:
Jan. 13 - Negotiated a revolving credit agreement with the bank. Amount available is $20m at prime rate.
Dec. 1 - Supported by credit line, issued $10m of commercial paper on a 9 month note. Interest was discounted at issuance at a 9% discount rate.
Dec. 31 - Record any necessary adjusting entry(s).
2014, Sept. 1 - Paid the commercial paper at maturity
Here's my question. Is this a scenario where I journalize this initially as:
12/1 - Cash (dr) 9.1m; Discount on notes payable (dr) 900,000; Notes payable (cr) 10m
My next question is this. I know I have to pro-rate the interest on 12/31, but do I do it at 1/12 or 1/9 since it is a 9 month note? So my next entry would be this?
12/31 - Interest expense (dr) ??; Accumulated interest (cr) ??
Then the payoff would be
9/1 - Notes payable (cr) 10m; Accumulated interest (cr) ??; Cash (dr) ??
I know I'm missing something here, and it's bothering me that I'm missing it. It's a fairly fundamental problem and I can't understand why I'm not getting it. Any help would be greatly appreciated.
2 AnswersHomework Help8 years agoPassenger side of 05 Dodge Caravan SXT not powering (X-posted in Dodge)?
I just purchased this van a couple of days ago and I noticed that the power features on the passenger side of the van are not functioning properly.
At first, all I noticed was that the power sliding door did not slide, so I searched some forums for that issue and saw everything from fixing wire breaks in the chain to taking it in to the dealer. When I push the slider button (either from the fob or from the interior of the vehicle) I can't even hear the motor engage. Also, the power door lock doesn't work on that door either. Then I noticed that the power window on the passenger front door doesn't work. Last night (my first time driving at night) I noticed that the passenger-side dome light also doesn't come on.
With everything happening on the same side, I'm not quite sure what to do. I checked my fuses and everything is lighting up green, so I'm guessing there may be something wrong with the wiring coming from the harness? Of course, I don't know anything about electrical, so I may be way off here.
Has anyone heard of this happening before (or something similar)? And if so, what are my options? I consider myself pretty mechanically inclined, so I can do some things on my own if need be. I would much prefer the option of doing it myself and not having to pay the dealership an exorbitant amount of money. Any help would be greatly appreciated
1 AnswerMaintenance & Repairs9 years agoI need to get a 'legal' translation of a Mexican death certificate?
My fiancee's mother passed away last week, and she had some assets here in the United States for which he is a beneficiary. In order to be able to claim these assets, he needs a legal translation of her death certificate which, of course, is in Spanish. What exactly is a 'legal' translation? How long does it take? Is it crazy expensive?
Any help would be greatly appreciated. He is supposed to be getting the documents via DHL tomorrow, so the more information I have up front, the better prepared he will be.
If no one is able to definitively answer my question, if anyone can point me in the right direction as far as where to begin research, that would work too.Thank you in advance for your time and attention.
Law & Ethics9 years agoQuestion about p-series and convergence/divergence?
I know that ∑ (n=3)^∞ 1/(n-2)^3 is a p-series summation and since p > 1, it is convergent
However, is ∑(n=2)^∞ 1/(n lnn^2 also a p-series? And if so, would p = 2 and also therefore be convergent?
If it isn't a p-series, which test should I use on this one...Direct comparison? Ratio? I'm lost here.
3 AnswersMathematics10 years agoSequence question, solving steps?
I'm working on some homework dealing with sequiences, and I've pretty much got it down. When I'm not quite sure what to do, I check the solution manual and follow the step-by-step. Usually they make sense; this one doesn't.
The problem reads:
a_n={(2n-1)!/(2n+1)!}
The first step in solving it shows:
(2n-1)!/(2n+1)(2n)(2n-1)!
I have no idea where that denominator came from. I can't figure out what, if anything, they multiplied, divided, or factored in order to get from (2n+1)! to (2n+1)(2n)(2n-1)!. Can someone please explain?
1 AnswerMathematics10 years agoPartal fraction decomposition questiion?
The question is:
∫(x )/(x-6) dx
The first step in the solution says:
∫((x-6)+6 )/(x-6) dx
then,
∫(1+(6 )/(x-6))dx
My question is,, where did the (x-6)+6 in the numerator come from?
1 AnswerMathematics10 years agoEvaluate the Integral?
h(x)=∫2^(1/x) tan^(-1)t dt
where 2 is the lower limit and 1/x is the upper limit
I know that the final answer is
-[tan^(-1)(1/x)]/x^2
but I'm confused as to how it got there. The answer I got was
ln(x) tan^(-1)(1/x)
so can someone tell me where the -1/x^2 came from?
I hope this made sense. If not, let me know and I'll edit the question for clarification.
3 AnswersMathematics10 years agoTrig Identities and Integrals?
So, I'm working on trig integrals. I've got the first step down which is:
sin^4(3t)dt = (sin^2(3t))^2
My solutions manual then says
(sin^2(3t))^2 = [1/2(1 - cos6t)]^2dt
I know where the (1 - cos) part comes from, it's a trig identity, but how did the 3t become a 6t? And where did the 1/2 come from?
2 AnswersMathematics1 decade agoHow do I Simplify Square Roots?
I asked a similar question and got a good response, but now I need clarification on the response.
I was told that 6^5/2 = √6^5 and that 3^5/2 = √3^5 that I'm starting to understand.
Then the answerer went on to say that √6^5 = 36√6 and that √3^5 = 9√3...now I'm lost again.
Can someone take me, step by step please, how these roots were simplified? Having this algebra gap is really causing me problems in my Calculus class.
4 AnswersMathematics1 decade agoConverting from fractional exponents to fractions with radicals?
i just finished working a review question on integrals. I integrated correctly, but i didn't simplify as far as my instructor did, so I only got partial credit. My question is how do I get from my answer to her answer?
my answer was;
[ (2/5)6^(5⁄2) + 12(6^(1⁄2) ] - ⌊ (2/5)3^(5⁄2) + 12(3^(1⁄2) ]
(2/5 times 6 to the 5/2 + 12 times 6 to the 1/2) - (2/5 times 3 to the 5/2 + 12 times 3 to the 1/2)
her answer was;
(132√6)/5 - (78√3)/5
WTH? I know this is another algebra thing, but...as usual... the algebra escapes me. Can anyone help me understand what the heck she did/
2 AnswersMathematics1 decade agoA Question of Exponents - Basic Algebra Rule Probably?
I have an equation that needs to be squared. I'm doing it via the FOIL Method, but my solutions manual does it another way, and it's obvious what happened, but I'm guessing there is an old algebra rule that I forgot.
(2y-y^2)^2
When I FOIL it, I get 2y^4 + 4y^2 - 4y^3
but the solutions manual shows 4y^2 - y^4
Obviously it just squared each variable individually, but I was under the impression that you could not do that. Is there some rule that I missed? Eventually I have to integrate it, and I know how to do that part, but if I integrate the FOIL answer that I came up with I get a different answer than what is in the book...and therefore it is wrong.
2 AnswersMathematics1 decade ago2 more calculus substitution rule questions?
This time, I'm not going to go into all the details of the whole problem. Once I get this first part figured out, I can do the rest. So here are the two problems:
1. ∫ e^(1/x)/x^2 dx
therefore:
u=1/x
but then I get:
du=ln|x|
which is wrong, because the solutions manual says:
du=-1/x^2
2. ∫ x√(x-1) dx
therefore:
u=x-1
du=dx
So, I get:
u^(1/2) du
But the book gets:
(u+1)√u du
If you could tell me where I'm going wrong on these, I'd greatly appreciate it. It's this simple, detailed stuff that keeps knocking me. I understand the whole concept, it's just getting there that's becoming the issue.
3 AnswersMathematics1 decade agoAnother Calculus Substitution Rule Question?
Here's another "captain obvious" problem...I hope
The question:
∫ (cosx / sin^2 x) dx
I know that:
u = sin x
du = cos x
When I solve, I get:
∫du / u^2
∫u^(-2) du
-u^(-1)+C
-sinx+C
But the solutions manual gives:
∫ du / u^2
∫ u^(-2) du
((u^-1)/-1)+C
-(1/sinx)+C
The solutions manual and I agree on the first two steps, but after that, I get confused. Can someone tell me how it goes from
∫u^(-2) du
to
((u^-1)/-1)+C
and not
-u^(-1)+C
Thanks in advance for any help you can give. I'm going to have a couple more on here before the day is out, so if you like this kind of stuff, keep an eye out for me! :)
5 AnswersMathematics1 decade agoCalculus - Substitution Rule Question?
I actually understand how to work the problem, but as usual, I'm caught up on the algebra part of it.
Here is the problem:
∫(lnx)^2/x dx
Now, I know I need to find my u and du values, so I've got:
u = lnx
du = dx/x
According to the solutions manual I'm right so far, but then I get lost. It says that after I plug in my values, I should have:
∫u^2 du
If I take that integral and solve it out I get:
1/3 u^3+C
1/3(lnx)^3+C (which also matches the answer in the book)
But I don't know how it got from (lnx)^2/x to u^2. Can anyone help with this? I hope the way I asked it made sense.
2 AnswersMathematics1 decade agoOne more equation of tangent line problem?
The algebra part of these problems is tripping me up. 'sigh' Here we go:
Find and equation of the tangent line √x to the curve at the given point (1,1)
Plugged into the equation (f(a+h)-f(a))/h, I get:
(f(1+h)-f(1))/h
Now, putting the equation back in, I get:
(√(1+h)-√1)/h
Is this one of those instances, where I need to multiply the numerator and denominator by the reciprocal √(1+h)-√1) in order to clean up the radicals? Again, I know where to go once this portion is solved, I'm just plumb stuck here. Eventually, my final answer should be y= (1/2)x+1/2
And yes, I have to use the formula, we're not using quotient, product, or sum rules in this chapter. :)
1 AnswerMathematics1 decade agoEquation of the tangent line question?
I know this is a long question, and there are a lot of parenthesis here, but I'm trying to get as much detail out as possible, and my hopes is that by showing my steps, you can tell me where I went wrong. Please bear with me. :)
The question as reads is:
Find an equation of the tangent line to the curve at the given point y = (x - 1)/(x - 2) (3,2)
I know I'm supposed to use the equation lim h-->0 (f(a + h) - f(a))/h
When I set up the equation, I get (through the first couple of steps):
(f(3+h)-f(3))/h
((((3+h)-1)/((3+h)-2))-3)/h
(((2+h)/(1+h))-3)/h
Here is where it starts to go wrong (I think). Multiplying by the top denominator (1+h), I get:
(2+h-3(1+h))/(h(1+h))
Somehow from here, I am supposed to end up with the equation y = -x + 5
I know that when I get the answer from the first equation (which I'll label as ?), I then plug it in to:
y - 2 = ?(x - 3)
But without knowing what the value is from the first equation, I can't finish solving.
If you've gotten this far, congratulations for surviving the tedium! Now that the reading part is over, any help with the solving that you can provide would be greatly appreciated. Thank you soooooo very much in advance.
5 AnswersMathematics1 decade ago