3(y+6)=30 how do you solve?

Anonymous2006-09-19T22:13:15Z

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Easy Y=4 6 plus what times 3 is 30?.................

Spiritoso2006-09-20T05:38:03Z

3(y+6)=30

1. Multiply 3*y= 3y
2. Multiply 3*6=18
3. You now have 3y + 18 =30
4. Move 18 to the other side of the equation by subtracting 3y=30-18
5. 3y=30-18 or 3y=12
6. Divide both sides by 3: 3y/3=y and 12/3=4
7. Hence y=4

To check 3(4+6)=30 or 3(10)=30

Donna S2006-09-20T05:18:58Z

3(y+6)=30
3y + 3*6 =30
3y + 18 =30
3y +18 -18 =30 - 18
3y = 12
3y/3=12/3
y=4

Yeong w2006-09-20T05:13:44Z

First , multiple 3 into the bracket just like this answer : 3y+18=30. Then , let 18 go behind to 30 like this : 3y=30-18 . Lastly , 3y=12 , y=4

anondewd2006-09-20T05:11:45Z

okay, you need to find out what y is. 4+6=10, 10*3=30 so y is 4

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