3(y+6)=30 how do you solve?

Easy Y=4 6 plus what times 3 is 30?.................

3(y+6)=30

1. Multiply 3*y= 3y

2. Multiply 3*6=18

3. You now have 3y + 18 =30

4. Move 18 to the other side of the equation by subtracting 3y=30-18

5. 3y=30-18 or 3y=12

6. Divide both sides by 3: 3y/3=y and 12/3=4

7. Hence y=4

To check 3(4+6)=30 or 3(10)=30

3(y+6)=30

3y + 3*6 =30

3y + 18 =30

3y +18 -18 =30 - 18

3y = 12

3y/3=12/3

y=4

First , multiple 3 into the bracket just like this answer : 3y+18=30. Then , let 18 go behind to 30 like this : 3y=30-18 . Lastly , 3y=12 , y=4

okay, you need to find out what y is. 4+6=10, 10*3=30 so y is 4

12 because u use the distributive property and the left side becomes 3y+18=30 and u subtract 18 making 3y equal to 12 and if you divide by 3 you get 4

3y + 18 = 30

3y = 12

y = 12/3 = 4

Always Start with the brackets first. it this case, 'y' = 4

3(4+6)=30

y+6 = 10

y = 4

3y+18=30

3y=30 -18

3y=12

y=4 is the answer