square root in the numerator, square root in the denominator,and the whole thing square rooted, how do I solve

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interesting, lemme give u an example

what u meant was : (i assume)

2 #s, X and Y

[ (X^1/2) / (Y^1/2) ]^1/2

distribute, we have:
(X^1/2) ^ 1/2 / (Y ^ 1/2 ) ^1/2


simplify, we have

X^1/4 / Y^1/4

no square root can be on the bottom so we mutiply by Y^3/4 / Y ^ 3/4

we have:

(X^1/4 * Y^3/4 ) / Y which can be

{ [X (Y) ^3] ^ 1/4 }/ Y...Show more