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square root in the numerator, square root in the denominator,and the whole thing square rooted, how do I solve

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  • 1 decade ago
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    interesting, lemme give u an example

    what u meant was : (i assume)

    2 #s, X and Y

    [ (X^1/2) / (Y^1/2) ]^1/2

    distribute, we have:

    (X^1/2) ^ 1/2 / (Y ^ 1/2 ) ^1/2

    simplify, we have

    X^1/4 / Y^1/4

    no square root can be on the bottom so we mutiply by Y^3/4 / Y ^ 3/4

    we have:

    (X^1/4 * Y^3/4 ) / Y which can be

    { [X (Y) ^3] ^ 1/4 }/ Y

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