Using the Discriminant
Use the Discriminant to determine whether the quadratic equation has two soloutions, one solution, or no real solution.
4. 3xsquared-3x+5=0
5. -3xsquared+6x-3=0
6. xsquared-5x-10=0
Anonymous
Favorite Answer
It's pretty simple actually.
A discriminant is b² - 4ac. You find the a,b,c values in the equation: ax²+bx+c
if b²-4ac is a positive number than there are 2 solutions
if b²-4ac is equal to 0 than there is 1 solution
if b²-4ac is a negative number than there are no solutions
Now for your questions:
#4.
b² - 4ac
(-3)²-4(3)(5) = 0
9-60=0
-51=0
***There are no solutions
#5.
b²-4ac
(6)²-4(-3)(-3)
36-36=0
0=0
***There is 1 solution
#6.
b²-4ac
(-5)²-4(1)(-10)
25+40=0
65=0
***There are 2 solutions
Hope i helped :)
dudemcgee101
The discriminant is b^2 - 4ac , where the quadratic is in the form ax^2+bx+c. If it is negative, there is no real solution. If it is 0, there is exactly one solution. If it is positive, there are two solutions.
4. a = 3, b =-3, c=5
(-3)^2 - 4*3*5
9 - 60 < 0, so no real solutions.
5. a=-3, b=6, c=-3
6^2 - 4*-3*-3
36-36 = 0, so exactly one real solution.
6. a=1, b=-5, c=-10
(-5)^2 - 4*1*-10
25+40 > 0, so two real solutions.