While Arranging objects if the order of objects is considered then such arrangement is called Permutation while if the order is not considered its called Combination
cidyah
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This is a combination problem.
3 boys can be chosen out of 12 in 12C3 ways. 2 girls can be chosen out of 8 in 8C2 ways.
So, the total number of ways is (12C3)(8C2)
12C3 = 12 ! / 3! 9 ! = 220
8C2 = 8! / 2! 6! = 28
No of ways = 220 x 28 = 6160
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1st boy 12 techniques 2d boy 11 techniques third boy 10 techniques form of techniques 3 boys could be chosen from 12 is 12x11x10 1st lady 8 techniques 2d lady 7 techniques form of techniques 2 women could be chosen from 8 is 8x7
sv
in C(12, 3)*C(8, 2) ways = 220*28 ways = 6160 ways.