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sana A
sana A asked in Science & MathematicsMathematics · 1 decade ago

The members of a club are 12 boys and 8 girls. In how many ways can a committee of 3 boys and 2 girls be forme

While Arranging objects if the order of objects is considered then such arrangement is called Permutation while if the order is not considered its called Combination

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  • cidyah
    Lv 7
    1 decade ago
    Favorite Answer

    This is a combination problem.

    3 boys can be chosen out of 12 in 12C3 ways. 2 girls can be chosen out of 8 in 8C2 ways.

    So, the total number of ways is (12C3)(8C2)

    12C3 = 12 ! / 3! 9 ! = 220

    8C2 = 8! / 2! 6! = 28

    No of ways = 220 x 28 = 6160

  • carattini
    Lv 4
    5 years ago

    1st boy 12 techniques 2d boy 11 techniques third boy 10 techniques form of techniques 3 boys could be chosen from 12 is 12x11x10 1st lady 8 techniques 2d lady 7 techniques form of techniques 2 women could be chosen from 8 is 8x7

  • sv
    Lv 7
    1 decade ago

    in C(12, 3)*C(8, 2) ways = 220*28 ways = 6160 ways.

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