Math help (should be easy)!?

I should know this, but I can't get my hea around it...

20% of m is 55
30% of n is 60

n is what percent of m?

73%
27%
138%
1.64%
.73%

How should I work this out? Any help would be appreciated!

?2008-10-28T21:27:55Z

Favorite Answer

First find what m is by dividing 55 by 20 and multiplying by 100.
Then find what n is by dividing 60 by 30 and multiplying by 100.
Then divide n by m and multiply by 100.
You'll have to round this answer up to the next #.

shinsplints992008-10-29T04:10:00Z

20% of m is 55
30% of n is 60

First find m and n:
20% = .2

.2m = 55

m = 55/.2

m = 275

30% = .3

.3n = 60

n = 60/.3

n = 200


200/275 x 100% = 72.727272727272... = 73%

mikah2008-10-29T04:12:55Z

73%.

.20m=55.
m= 275

.30n=60
n=200

therefore: 200/275 = x/100 --> x=72.7

philx92008-10-29T04:10:38Z

first solve for m and n

0.2m = 55
m= 55(0.2) = 275

0.3n=60
n=60(0.3) = 200

n/m = 200/275 = 0.727
So 73%

guttface2008-10-29T04:08:48Z

0.2m=55
0.3n=60

so:
m=275
n=200

n/m= 200/275 = 0.727 = 72.7% = 73% when rounded