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An Easy Math Problem For Easy Points...?
Heres an easy math problem for easy points...
the first one to get it correct wins I guess?
Heres The Question:
Of 29 students14 are wearing red, 12 are wearing blue, and 5 arent wearing any.
How many people are:
Red and blue?
Red and not blue?
Blue and not red?
P.S. Some people are wearing more than one color...
Hope its easy enough...
12 Answers
- Anonymous1 decade agoFavorite Answer
red and blue - 26
red & not blue : 19
blue and not red : 17
i think thats right
- science_guyLv 51 decade ago
14 + 12 + 5 = 31
so 2 students are wearing both
a) 14+12-2 = 24
b) 14-2 = 12
c) 12-2 = 10
Please note that alot of people will answer 26 for the first question, however this is incorrect:
29 - 5 = 24 (minus of people who arent wearing red OR blue
14+12 = 26 there is 26 blue and red colours but only 24 students this means 2 people must be wearing both colours
as I just mentioned there is only 24 people so how many red and blue = 24
red not blue = red people less the people who wearing both
blue not red = blue people less the people who wearing both
- Anonymous1 decade ago
Red+Blue: 24 students
Red: 12 students
Blue: 12 students
Dunno... im in a rush just checking it out
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- Anonymous5 years ago
let x be the first [smaller] of the two numbers and y be the second [larger] x + y = 140 y/x = 9/5 so y = 140 - x (140 - x)/x = 9/5 cross multiply 5(140 - x) = 9x 700 - 5x = 9x 700 = 14x x = 50 and since x + y = 140, y = 140 - 50 = 90
- Anonymous1 decade ago
1) 26
2)19
3) 19
- 1 decade ago
red and blue- 2
red not blue- 12
blue not red- 10
none- 5
worked it out on paper.