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An Easy Math Problem For Easy Points...?

Heres an easy math problem for easy points...

the first one to get it correct wins I guess?

Heres The Question:

Of 29 students14 are wearing red, 12 are wearing blue, and 5 arent wearing any.

How many people are:

Red and blue?

Red and not blue?

Blue and not red?

P.S. Some people are wearing more than one color...

Hope its easy enough...

12 Answers

Relevance
  • Anonymous
    1 decade ago
    Favorite Answer

    red and blue - 26

    red & not blue : 19

    blue and not red : 17

    i think thats right

  • 1 decade ago

    14 + 12 + 5 = 31

    so 2 students are wearing both

    a) 14+12-2 = 24

    b) 14-2 = 12

    c) 12-2 = 10

    Please note that alot of people will answer 26 for the first question, however this is incorrect:

    29 - 5 = 24 (minus of people who arent wearing red OR blue

    14+12 = 26 there is 26 blue and red colours but only 24 students this means 2 people must be wearing both colours

    as I just mentioned there is only 24 people so how many red and blue = 24

    red not blue = red people less the people who wearing both

    blue not red = blue people less the people who wearing both

  • 1 decade ago

    29

  • Anonymous
    1 decade ago

    Red+Blue: 24 students

    Red: 12 students

    Blue: 12 students

    Dunno... im in a rush just checking it out

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  • Anonymous
    5 years ago

    let x be the first [smaller] of the two numbers and y be the second [larger] x + y = 140 y/x = 9/5 so y = 140 - x (140 - x)/x = 9/5 cross multiply 5(140 - x) = 9x 700 - 5x = 9x 700 = 14x x = 50 and since x + y = 140, y = 140 - 50 = 90

  • red and blue 2

    only red 12

    only blue 10

  • 1 decade ago

    1. 26

    2. 14

    3. 12

  • Anonymous
    1 decade ago

    1) 26

    2)19

    3) 19

  • 1 decade ago

    26

    14 or 19

    12 or 17

  • 1 decade ago

    red and blue- 2

    red not blue- 12

    blue not red- 10

    none- 5

    worked it out on paper.

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