i have a triangle all 3 sides are identicle one side is 7p another is q+10 and the last is 2(p-3q) find the...?

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If all 3 sides are identical
Side A = 7p
Side B = q+10
Side C = 2p - 6q

So,
7p = 2p - 6q
5p = -6q
p = (-6/5)q

Side A = 7 * (-6/5)q = (-42/5)q
Side B = q + 10

(-42/5)q = (5/5)q + 10
(-47/5)q = 10
q = -50/47
p = (-6/5)(-50/47) = 60 / 47
So, p = 60/47 and q = -50/47

The perimeter = 7p + q+10 + 2p - 6q = 9p - 5q + 10
9(60/47) - 5( -50/7) + 10 = 540/47 + 250/47 + 470/47 = 1260/47
The perimeter is 1260/47...Show more

does it give you anymore information?...Show more