physics help please (coefficients of friction)?

i pretty much have the entire chapter down but i can't figure out his part

a 1000 N crate is being pushed across a level floor at a constant speed by a force of 300N at an angle of 20 degrees below the horizontal (such as someone is pushing it from behind, at a downward angle) what is the coefficient of kinetic friction between the crate and the floor?

i don't need an answer as much as i just need to be shown how to do it

Steve2009-03-07T16:19:01Z

Favorite Answer

The total downward (normal) force Fn = W + 300sin20°

The frictional force is therefore Ff = µ*Fn.

But Ff also = 300cos20°

Setting these last 2 equal, µ = [300cos20°]/Fn