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erratic
erratic asked in Science & MathematicsPhysics · 1 decade ago

physics help please (coefficients of friction)?

i pretty much have the entire chapter down but i can't figure out his part

a 1000 N crate is being pushed across a level floor at a constant speed by a force of 300N at an angle of 20 degrees below the horizontal (such as someone is pushing it from behind, at a downward angle) what is the coefficient of kinetic friction between the crate and the floor?

i don't need an answer as much as i just need to be shown how to do it

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  • Steve
    Lv 7
    1 decade ago
    Favorite Answer

    The total downward (normal) force Fn = W + 300sin20°

    The frictional force is therefore Ff = µ*Fn.

    But Ff also = 300cos20°

    Setting these last 2 equal, µ = [300cos20°]/Fn

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