Math Question, Word Problem?

The drama club sold 1500 tickets for the end of the year performance. Admission prices were $12 for adults. $6 for students. The total amount collected at the box office was $15,480. How many students attended the play?

Jun Agruda2009-04-20T00:51:57Z

Favorite Answer

No. of adult tickets (x):
$12.00x + $6.00(1,500 - x) = $15,480.00
2x + 1,500 - x = 2,580
x = 1,080

No. of student tickets:
= 1,500 - 1,080
= 420

Answer: adult tickets, 1,080; student tickets, 420

Proof ($15,480.00 was the total collection):
= $12.00(1,080) + $6.00(420)
= $12,960.00 + $2,520.00
= $15,480.00

camuigckt4272009-04-20T07:55:33Z

First, make a problem set! :D

Let the variable "a" represent the adults and "s" represent the students:

#1: 12a+6s=15480 (this represents how much was collected from everyone
#2: a+s=1500 (this is to represent the attendance)

We need to find just one of the variables first. You want to know how many students attended the play, so we're going to find the value of "s".

We'll start with "a+s=1500". To find s, we'll need to multiply both sides of the equation with 12, since we will subtract this equation from equation #1.

12(a+s)=12(1500)
12a+12s=18000

Next

12a+6s=15480 <-equation #1
-(12a+12s) -(18000) (what we got from equation #2, distribute that negative sign! :D)

We get:
-6s=-2520 divide both sides by (-6)
s=420

420 students attended the play! ^_^

yntet2009-04-20T07:53:59Z

Let x be the number of students who watched/attended the play
so, the number of adults who attended the play can be represented as (1500-x)

Working equation:

6x+12(1500-x)= 15 480

solving for x,

6x+18 000-12x= 15480

6x-12x= 15480-18000

-6x = -2520
x=420


420 students attended the play

mathdreams2009-04-20T07:59:53Z

x is the number of adult tickets sold and y is the number of student tickets sold

12x + 6y = 15,480
x+y=1500

x = 1500-y
12(1500-y) + 6y = 15,480
18,000 -12y + 6y = 15,480
18,000 - 6y = 15,480
-6y = 15,480 - 18,000
-6y = -2520
y = -2520/-6
y = 420

420 students attended the play