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Math Question, Word Problem?
The drama club sold 1500 tickets for the end of the year performance. Admission prices were $12 for adults. $6 for students. The total amount collected at the box office was $15,480. How many students attended the play?
4 Answers
- Jun AgrudaLv 71 decade agoFavorite Answer
No. of adult tickets (x):
$12.00x + $6.00(1,500 - x) = $15,480.00
2x + 1,500 - x = 2,580
x = 1,080
No. of student tickets:
= 1,500 - 1,080
= 420
Answer: adult tickets, 1,080; student tickets, 420
Proof ($15,480.00 was the total collection):
= $12.00(1,080) + $6.00(420)
= $12,960.00 + $2,520.00
= $15,480.00
- 1 decade ago
First, make a problem set! :D
Let the variable "a" represent the adults and "s" represent the students:
#1: 12a+6s=15480 (this represents how much was collected from everyone
#2: a+s=1500 (this is to represent the attendance)
We need to find just one of the variables first. You want to know how many students attended the play, so we're going to find the value of "s".
We'll start with "a+s=1500". To find s, we'll need to multiply both sides of the equation with 12, since we will subtract this equation from equation #1.
12(a+s)=12(1500)
12a+12s=18000
Next
12a+6s=15480 <-equation #1
-(12a+12s) -(18000) (what we got from equation #2, distribute that negative sign! :D)
We get:
-6s=-2520 divide both sides by (-6)
s=420
420 students attended the play! ^_^
- 1 decade ago
Let x be the number of students who watched/attended the play
so, the number of adults who attended the play can be represented as (1500-x)
Working equation:
6x+12(1500-x)= 15 480
solving for x,
6x+18 000-12x= 15480
6x-12x= 15480-18000
-6x = -2520
x=420
420 students attended the play
Source(s): 7th grade algebra - 1 decade ago
x is the number of adult tickets sold and y is the number of student tickets sold
12x + 6y = 15,480
x+y=1500
x = 1500-y
12(1500-y) + 6y = 15,480
18,000 -12y + 6y = 15,480
18,000 - 6y = 15,480
-6y = 15,480 - 18,000
-6y = -2520
y = -2520/-6
y = 420
420 students attended the play