algebra 2;; f(x)=2-x^2?

ok so i have no clue how to do this equation for algebra 2
f(x)=2-xsquared

2009-06-01T08:37:55Z

and how to your GRAPH IT

?2009-06-01T08:48:06Z

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if u mean to solve 2 - x^2 = 0 then

x^2 = 2

x = +/- sqrt(2)

it's easy to graph, first find the vertex which is located at (0,2)
then draw the 2 x-int points on the x axis and match between the vertex and these two poinrs

Anonymous2009-06-01T08:50:52Z

f(x) is called a function (said f of x)
it represents the "Y" coordinate on a Cartesian plane.

If they ask you to evaluate f(x) = 2-(x^2) at a certain number, say x=3, then here is what you do...

Re-write the function as f(3) = 2-(x^2) " f of 3 = 2 minus x squared"

replace the x in the equation with the number in parenthesis...
remember to follow the order of operations

f(3) = 2-(x^2) " f of 3 = 2 minus x squared"

f(3) = 2-(3^2) " f of 3 = 2 minus 3 squared"

f(3) = (2-9) " f of 3 = 2 minus 9"

f(3) = -7 Answer: " f of 3 = negative 7"

Follow these steps for whatever number they ask you to evaluate the function at.
So for X=3, Y= -7 giving you the ordered pair (3,-7)
you can get an ordered pair you can graph for any number you wish to evaluate the function at.

Medianoche122009-06-01T08:44:20Z

-x^2+2=0 (I just rewrote it here, with the x term in front)
-x^2=-2 (Subtract the 2 to the other side)
x^2=2 (Get rid of the negatives [multiply by -1])
x=plus or minus the square root of 2

I think that's it. It's been a while since Algebra II, though. :)

As for graphing it: http://www.analyzemath.com/Graphing/graphing_square_root_func.html

tfrobinhood2009-06-01T08:41:11Z

what are you solving for?

f(x) = 2 - x^2 is just the equation. you can't solve for x unless you have something on the other side...such as:
0 = 2 - x^2

in that case, if it is 0, you would subtract 2...
-2 = -x^2

drop the negative sign

2 = x^2

then take the square root

sqrt(2) = x

Lori2016-04-05T08:12:05Z

Move everything to the left side: X^2 - 3x + 8 = 0 Use the quadratic formula (look it up) to find the roots. a = 1 b = -3 c = 8

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