algebra 2;; f(x)=2-x^2?

if u mean to solve 2 - x^2 = 0 then

x^2 = 2

x = +/- sqrt(2)

it's easy to graph, first find the vertex which is located at (0,2)

then draw the 2 x-int points on the x axis and match between the vertex and these two poinrs

f(x) is called a function (said f of x)

it represents the "Y" coordinate on a Cartesian plane.

If they ask you to evaluate f(x) = 2-(x^2) at a certain number, say x=3, then here is what you do...

Re-write the function as f(3) = 2-(x^2) " f of 3 = 2 minus x squared"

replace the x in the equation with the number in parenthesis...

remember to follow the order of operations

f(3) = 2-(x^2) " f of 3 = 2 minus x squared"

f(3) = 2-(3^2) " f of 3 = 2 minus 3 squared"

f(3) = (2-9) " f of 3 = 2 minus 9"

f(3) = -7 Answer: " f of 3 = negative 7"

Follow these steps for whatever number they ask you to evaluate the function at.

So for X=3, Y= -7 giving you the ordered pair (3,-7)

you can get an ordered pair you can graph for any number you wish to evaluate the function at.

-x^2+2=0 (I just rewrote it here, with the x term in front)

-x^2=-2 (Subtract the 2 to the other side)

x^2=2 (Get rid of the negatives [multiply by -1])

x=plus or minus the square root of 2

I think that's it. It's been a while since Algebra II, though. :)

As for graphing it: http://www.analyzemath.com/Graphing/graphing_squar...

what are you solving for?

f(x) = 2 - x^2 is just the equation. you can't solve for x unless you have something on the other side...such as:

0 = 2 - x^2

in that case, if it is 0, you would subtract 2...

-2 = -x^2

drop the negative sign

2 = x^2

then take the square root

sqrt(2) = x

Move everything to the left side: X^2 - 3x + 8 = 0 Use the quadratic formula (look it up) to find the roots. a = 1 b = -3 c = 8

Replace the x with 2-x.

so now the equation looks like this 2-(2-x)^2

2-2+x^2

x^2.

Sorry i dont know what^ means...=]'x

2 times f times x is equal to 2 times x squared I think :P

Download graphsketch from google

To get a sure answer I check out http://www.thebeehive.org/ ITS free to use and they help with just about any school work

x = +/- sqrt(2)

This is a parabola. It's vertex is at (0,2), its x-intercepts are +/- sqrt(2), its axis of symmetry is the y-axis, the vertex is a max value of 2, the parabola opens downward.