Part of a parametric differentiatiton question?
I need to differentiate
y= t^5 + (20t^3 / 3)
i did it like this, but im not sure if it's right :
5t^4 + (60t)/3 -----> 5t^4 + 20t
I need to differentiate
y= t^5 + (20t^3 / 3)
i did it like this, but im not sure if it's right :
5t^4 + (60t)/3 -----> 5t^4 + 20t
Denis S
Favorite Answer
Almost,
d(t^3)/dt=3t^2
So then,
(20/3)t^3---> (20/3)(3t^2)=20t^2
Ali
You had a little mistake:
d/dt(20t^3) = 60t^2
so 5t^4 + (60t^2)/3 -----> 5t^4 + 20t^2