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henblantbach
henblantbach asked in Science & MathematicsMathematics · 1 decade ago

Part of a parametric differentiatiton question?

I need to differentiate

y= t^5 + (20t^3 / 3)

i did it like this, but im not sure if it's right :

5t^4 + (60t)/3 -----> 5t^4 + 20t

2 Answers

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  • Denis S
    Lv 6
    1 decade ago
    Favorite Answer

    Almost,

    d(t^3)/dt=3t^2

    So then,

    (20/3)t^3---> (20/3)(3t^2)=20t^2

  • Ali
    1 decade ago

    You had a little mistake:

    d/dt(20t^3) = 60t^2

    so 5t^4 + (60t^2)/3 -----> 5t^4 + 20t^2

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