Percentage Error of MgO?

Don't know how to find it...

I have 0.081 grams of MgO

with 0.05 grams of Mg

punkie2010-01-13T15:22:51Z

Favorite Answer

2Mg + O2 -----> 2MgO


If you started with 0.05g Mg and all of it reacted, you should have gotten

.05g Mg x 1 mole / 24.3g x 2 moles MgO / 2 moles Mg x 40.3g / 1 mole = 0.083 g MgO

You got .082g MgO.

% error = error / accepted value x 100 = 0.001g / 0.083g x 100 = 1.2% error

NOT BAD!