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Percentage Error of MgO?
Don't know how to find it...
I have 0.081 grams of MgO
with 0.05 grams of Mg
1 Answer
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- punkieLv 51 decade agoFavorite Answer
2Mg + O2 -----> 2MgO
If you started with 0.05g Mg and all of it reacted, you should have gotten
.05g Mg x 1 mole / 24.3g x 2 moles MgO / 2 moles Mg x 40.3g / 1 mole = 0.083 g MgO
You got .082g MgO.
% error = error / accepted value x 100 = 0.001g / 0.083g x 100 = 1.2% error
NOT BAD!
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